issues_labels

1 row where issues_id = 1817880272

✎ View and edit SQL

This data as json, CSV (advanced)

CREATE TABLE [issues_labels] (
   [labels_id] INTEGER REFERENCES [labels]([id]),
   [issues_id] INTEGER REFERENCES [issues]([id]),
   PRIMARY KEY ([issues_id], [labels_id])
);
CREATE INDEX [idx_issues_labels_issues_id]
    ON [issues_labels] ([issues_id]);
CREATE INDEX [idx_issues_labels_labels_id]
    ON [issues_labels] ([labels_id]);