issue_comments: 531674432

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https://github.com/pydata/xarray/pull/3302#issuecomment-531674432 https://api.github.com/repos/pydata/xarray/issues/3302 531674432 MDEyOklzc3VlQ29tbWVudDUzMTY3NDQzMg== 1941408 2019-09-16T07:50:26Z 2019-09-16T07:50:26Z CONTRIBUTOR

Thanks @stefraynaud . I'm having trouble figuring out defining the length of a gap in the irregular coordinate case.

e.g.

da4 = xr.DataArray([np.nan, np.nan, np.nan, 1, np.nan, np.nan, 4, np.nan, np.nan], dims=["y"], coords={"y": [0, 2, 5, 6, 7, 8, 10, 12, 14]})

<xarray.DataArray (y: 9)> array([nan, nan, nan, 1., nan, nan, 4., nan, nan]) Coordinates: * y (y) int64 0 2 5 6 7 8 10 12 14

What is the length of these three gaps given that xarray doesn't have any understanding of grids?

@dcherian In your example, as said @max-sixty, the middle gap has a length of 10-6=4. The length gaps at the edges cannot be computed but it doesn't matter, and the algo should work as when simply counting the nans.

I'll have a look the code, maybe for a new PR after this one.

 
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