html_url,issue_url,id,node_id,user,created_at,updated_at,author_association,body,reactions,performed_via_github_app,issue
https://github.com/pydata/xarray/pull/3302#issuecomment-531674432,https://api.github.com/repos/pydata/xarray/issues/3302,531674432,MDEyOklzc3VlQ29tbWVudDUzMTY3NDQzMg==,1941408,2019-09-16T07:50:26Z,2019-09-16T07:50:26Z,CONTRIBUTOR,"> 
> 
> Thanks @stefraynaud . I'm having trouble figuring out defining the length of a gap in the irregular coordinate case.
> 
> e.g.
> 
> ```
> da4 = xr.DataArray([np.nan, np.nan, np.nan, 1, np.nan, np.nan, 4, np.nan, np.nan], 
>                    dims=[""y""], coords={""y"": [0, 2, 5, 6, 7, 8, 10, 12, 14]})
> ```
> 
> ```
> <xarray.DataArray (y: 9)>
> array([nan, nan, nan,  1., nan, nan,  4., nan, nan])
> Coordinates:
>   * y        (y) int64 0 2 5 6 7 8 10 12 14
> ```
> 
> What is the length of these three gaps given that xarray doesn't have any understanding of grids?

@dcherian  In your example, as said @max-sixty, the middle gap has a length of `10-6=4`. The length gaps at the edges cannot be computed but it doesn't matter, and the algo should work as when simply counting the nans.

I'll have a look the code, maybe for a new PR after this one.","{""total_count"": 0, ""+1"": 0, ""-1"": 0, ""laugh"": 0, ""hooray"": 0, ""confused"": 0, ""heart"": 0, ""rocket"": 0, ""eyes"": 0}",,492866552
https://github.com/pydata/xarray/pull/3302#issuecomment-531248632,https://api.github.com/repos/pydata/xarray/issues/3302,531248632,MDEyOklzc3VlQ29tbWVudDUzMTI0ODYzMg==,1941408,2019-09-13T14:00:30Z,2019-09-13T14:00:30Z,CONTRIBUTOR,"Nice feature.
How about adding the support max gaps expressed in physical units, since coordinates may be irregular?","{""total_count"": 0, ""+1"": 0, ""-1"": 0, ""laugh"": 0, ""hooray"": 0, ""confused"": 0, ""heart"": 0, ""rocket"": 0, ""eyes"": 0}",,492866552